4^1-x=(1/4)^2x-3

Solution for 4^1-x=(1/4)^2x-3 equation:

4^1-x=(1/4)^2x-3

We move all terms to the left:

4^1-x-((1/4)^2x-3)=0


Domain of the equation: 4)^2x-3)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-x-((+1/4)^2x-3)+4^1=0

We add all the numbers together, and all the variables

-1x-((+1/4)^2x-3)+4=0

We multiply all the terms by the denominator


-1x*4)^2x-3)-((+4*4)^2x-3)+1=0

We add all the numbers together, and all the variables

-1x*4)^2x-3)-(16^2x-3)+1=0

Wy multiply elements

-4x^2=0

a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-8}=0$